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VMariaS [17]
3 years ago
11

H(8) = -2(8)^2 + 4(8)- 7

Mathematics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

h = - 103/8

Step-by-step explanation:

1) Re-order terms so constants are on the left

8h = = -2(8)²+4(8)-7

2) Evaluate the exponent

8h = -2·64+4(8)-7

3) Multiply the numbers

8h = -128+4(8)-7

4) Multiply the numbers

8h = -128+32-7

5) Add the numbers

8h = -103

6) Divide both sides of the equation by the same term

8h/8 = -103/8

7) Simplify

- Cancel terms that are in both the numerator and denominator

h = -103/8

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Solve by completing the square.
IRINA_888 [86]

Answer:

-23.18, -0.82

Step-by-step explanation:

  • h² + 24h + 19 = 0
  • h²+2h*12+12²-125=0
  • (h+12)²-√125²=0
  • (h+12+11.18)(h+12-11.18)=0
  • (h+23.18)(h+0.82)=0
  • h+23.18=0 ⇒ h= -23.18
  • h+0.82=0 ⇒ h= -0.82
7 0
3 years ago
Read 2 more answers
The profits of mr cash’s company is represented by the equation p(t)=-3t^2+18t-4, where p(t) is the amount of profit in hundreds
Anika [276]

Answer:

  • $2300000- max profit
  • 5.77 years into operation - zero profit time

Step-by-step explanation:

<u>Given function:</u>

  • p(t)= -3t^2 + 18t - 4

It is a quadratic function with general form of y = ax^2 + bx + c

It opens down if a < 0 and gets maximum value at vertex which is determined at x = -b/2a

<u>For the given function vertex is:</u>

  • t = -18/-3*2 = 3

<u>Maximum value of p is:</u>

  • p(3) = -3*3^2 + 18*3 - 4 = -27 + 54 - 4 = 23 ($2300000)

<u>The time when profit is zero:</u>

  • -3t^2 + 18t - 4 = 0
  • 3t^2 - 18t + 4 = 0
  • t = (18 ± √18² - 4*3*4)/2*3 = (18 ± √276)/6 = (18 ± 16.61)/6
  • t = (18 - 16.61)/6 = 0.23 this is the time when company has just started to make profit, it is not applicable as is the past time
  • t =  (18 + 16.61)/6 = 5.77 years into operation, after this time there will be no profit
5 0
3 years ago
Which of the following decimals has the greatest value 6.362 6.537 6.5 6.58
Lilit [14]

Answer:

6.58 has the greatest value

6.362 < 6.5 < 6.537 < 6.58

7 0
3 years ago
Read 2 more answers
Suppose an and bn are series with positive terms and bn is known to be convergent. (a) If an &gt; bn for all n, what can you say
yawa3891 [41]

Answer:

a. i. We cannot say anything about aₙ

ii. we do not know if the terms of aₙ are increasing or decreasing

b. i. aₙ converges by the Comparison Test.

ii. aₙ also converges since bₙ.

Step-by-step explanation:

(a)

i) If aₙ > bₙ for all n, what can you say about aₙ ? Why?

We cannot say anything about an.

ii) Why?

This is because since ∑bₙ converges, ∑aₙ > ∑bₙ, we do not know if the terms of aₙ are increasing or decreasing, so we have no information about it.  

(b) If aₙ < bₙ for all n, what can you say about aₙ ? Why?

i) aₙ converges by the Comparison Test.

ii) Why?

This is because since ∑bₙ converges, and ∑aₙ < ∑bₙ, we know that the terms of aₙ are also decreasing and, by the comparison test, aₙ also converges since bₙ.

7 0
3 years ago
A carnival has two payment options. Plan A, you pay $10 admission plus $3 for each ride. Plan B, you pay a $20 admission plus $1
stiks02 [169]
<span>Let x = # of rides

Plan A: 10 + 3x

Plan B: 20 + x

if x < 5 rides then plan A is better buy
if x = 5 both plans are the same
if x > 5 then plan B is the best buy

Prove:
x = 6 (rides)

plan A: </span>10 + 3x = 10 + 3(6) = 10+18 = $28
plan B: 20 + x = 20 + 6 = $26


3 0
3 years ago
Read 2 more answers
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