hit the sign in botten or create new account
Answer:
The diagram of the ER and depreciation is in the attachments.
Answer:
void delete_record(student_record *arr, int &size, int age, string name, double gpa) {
int index = -1;
if (arr != NULL && size > 0) {
for (int i = 0; i < size; ++i) {
if (arr[i].age == age && arr[i].name == name && arr[i].gpa == gpa) {
index = i;
break;
}
}
}
if (index != -1) {
for (int i = index; i < size - 1; ++i) {
arr[i] = arr[i + 1];
}
size--;
}
}
The range of cells in column A and rows 10 through 20
Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// string array
string m[3];
// array to store rainfall
double rainfall[3];
// variables
double avg_rainfall,sum=0;
for(int i=0;i<3;i++)
{
cout<<"Enter name of month "<<i+1<<" :";
// read month name
cin>>m[i];
cout<<"Enter rainfall (inches) in month "<<i+1<<" :";
// read rainfall
cin>>rainfall[i];
// sum of rainfall
sum+=rainfall[i];
}
// Average rainfall
avg_rainfall=sum/3;
// print Average rainfall
cout<<"Average rainfall for "<<m[0]<<","<<m[1]<<","<<m[2]<<" is "<<avg_rainfall<<" inches."<<endl;
return 0;
}
Explanation:
Create string array "m" to store name of month and double array "rainfall" to store rainfall. Read name of 3 months and rainfall in that month.Find the sum of all the rainfall and the average rainfall.Print the average rainfall of 3 months.
Output:
Enter rainfall (inches) in month 2 :45
Enter name of month 3 :july
Enter rainfall (inches) in month 3 :43
Average rainfall for may,june,july is 42.6667 inches.
