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Svetllana [295]
2 years ago
11

What is the y-intercept y = -6x - 5

Mathematics
2 answers:
Jet001 [13]2 years ago
6 0
Hello. The y-intercept is (0,-5).
lesantik [10]2 years ago
3 0

Answer:

(0,-5)

Step-by-step explanation:

Hope this helps :)

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Can someone please help me!!!
egoroff_w [7]
The correct answer is the first one(a): To get the system B,..., the first equation multiplied by 4...

Explanation:

1. Let us first multiple the first equation in System A with 4, we would get:
4(2x - y) = 4 * 3

=> 8x - 4y = 12 --- (A)

Now add the equation (A) and the second equation of System A:

8x  - 4y = 12
3x + 4y = 10
------------------
11x = 22 

Hence,
System B:
2x - y = 3
11x = 22

-i
5 0
3 years ago
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Please help!!!!!!!!!!!!!!
Talja [164]

Answer:

6 and 4

Step-by-step explanation:

8 0
3 years ago
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The figure below is a square. Find the length of side x in simplest radical form with a rational denominator.
Mashcka [7]

Answer:

\frac{\sqrt{10}}{2}

Step-by-step explanation:

The diagonal forms two 45-45-90 triangles, with the diagonal being the hypotenuse of both. The Pythagorean Theorem states that a^2+b^2=c^2, where c is the hypotenuse of the triangle, and a and b are the two legs of the triangle.

From the Isosceles Base Theorem, the two legs of a 45-45-90 triangle are always equal. Since we're given a diagonal of \sqrt{5}, we have:

x^2+x^2=\sqrt{5}^2,\\2x^2=5,\\x^2=\frac{5}{2},\\x=\sqrt{\frac{5}{2}}=\frac{\sqrt{5}}{\sqrt{2}}=\frac{\sqrt{5}}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\boxed{\frac{\sqrt{10}}{2}}

7 0
3 years ago
What is the volume of a rectangular prism with the dimensions: base 3 8 cm, height 1 3 cm, and length 3 4 cm
dusya [7]

The answer is 16,796 cm

6 0
3 years ago
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2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
3 years ago
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