Answer:
yes
Step-by-step explanation:
The graph is of a function (one output for every input) that also passes the horizontal line test (one input for every output). Hence it is one-to-one.
For a <em>function</em>, the key for it being one-to-one is that it pass the horizontal line test.
Step-by-step explanation:
factor 4 out of the variable terms, as this helps.
but my approach is simply to define the target and then calculate "backwards".
we want to find
(ax + b)² = a²x² + 2abx + b²
and now we compare with the original equation :
a²x² = 4x²
a² = 4
a = 2
2abx = 16x
2×2×bx = 16x
4b = 16
b = 4
b² = 16, but we have only 3, so we need to subtract 16-3 = 13 from the completed square.
so, our equation is
(2x + 4)² - 13 = 0
(2x + 4)² = 13
2x + 4 = sqrt(13)
2x = sqrt(13) - 4
x = sqrt(13)/2 - 2
Yes, I shall give you an idea of how to start it. :)
Today I feel glad...
For all the friends I have had...
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Ta da! :D Hope you like it
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