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2 years ago

6

Which is the best unit to use for measuring the length of an eyelash

1 answer:

Fofino [41]2 years ago

8 0

millimeter is the anwser

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uan spent 10 minutes on his history homework and 3 minutes per question on his math homework. Which graph shows the total homewo

never [62]

Answer: Im tying to figure it out but i cant sorry do youre best

Step-by-step explanation:

DO IT

4 0

2 years ago

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Write 7.75 x 10^-3 in standard notation

Natasha_Volkova [10]

Answer:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

7.75 × 10^−3

4 0

3 years ago

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Factorise 9w² - 100<br><br><br>

ohaa [14]

Answer:

$9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10)$ .

Step-by-step explanation:

Fact:

$\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}$ .

In other words, $(a^{2} - b^{2})$ , the difference of two squares in the form $a^{2}$ and $b^{2}$ , could be factorized into $(a - b)\, (a + b)$ .

In this question, the expression $(9\, w^{2} - 100)$ is the difference between two terms: $9\, w^{2}$ and $100$ .

$9\, w^{2}$ is the square of $3\, w$ . That is: $(3\, w)^{2} = 9\, w^{2}$ .
On the other hand, $10^{2} = 100$ .

Hence:

$9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}$ .

Apply the fact that $a^{2} - b^{2} = (a - b) \, (a + b)$ to factorize this expression. (In this case, $a = 3\, w$ whereas $b = 10$ .)

$\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}$ .

8 0

3 years ago

Distribute -2(6x^2+6)

BabaBlast [244]

Answer:

-12

Step-by-step explanation:

3 0

3 years ago

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PEASE HELP! The table below shows the values of y for different values of x:

Shkiper50 [21]

<span>A) y = 3x because the slope (rate of change) is 3. The y-intercept is 0 so we don't necessarily need to add anything else.
</span>

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3 years ago

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