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postnew [5]
3 years ago
10

How do you solve for area and perimeter

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0
Find the measure of the third angle

Use your trig functions the get the sides

Then calculate area and perimeter
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What is the slope of the line that passes through the given points (2,12) and (6,11)
Naily [24]

Answer:

-1/4

Step-by-step explanation:

You would use rise over run:

12-11/2-6

When simplified, this is -1/4

5 0
3 years ago
Can anyone help me with my homework
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3 0
3 years ago
Randy divides (2x4 – 3x3 – 3x2 + 7x – 3) by (x2 – 2x + 1) as shown below. What error does Randy make?
jarptica [38.1K]

error is in constant term of quotient


4 0
4 years ago
Read 2 more answers
Is a directed segment with endpoints A(2,2) and B(14,14). In two or more complete sentences, explain how you would verify that P
aleksley [76]
You can verify that Point X, with coordinate of (6,6) divides in a 1:2 ratio by finding the distance between points A and B. Doing so, you will find that the distance between points A and B is equal to 12, so 6 is half of 12. Therefore, the point (6,6) or X is halfway between points A and B(12), making the ratio 6:12 or simplified to 1:2.
4 0
3 years ago
Read 2 more answers
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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