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2 years ago

Laura bought 23 pounds of sugar for $12. How many dollars did she pay per pound of sugar?

Mathematics

1 answer:

Vikki [24]2 years ago

6 0

Answer:

≈ $0.52 per pound

Step-by-step explanation:

12/23 ≈ $0.52

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Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

2 years ago

Read 2 more answers

Gas station X charges $4.00 per gallon of gas. Gas station Y charges $4.12 per gallon of gas. What is the percent increase from

kirill [66]

First, find the increase in charge between the two station. That is:

$4.12-$4.00=$0.12

Then, divide the increase by the price charged by Gas Station X.

$0.12/$4.00=0.03

Lastly, since it is a decimal, transform it to percentage by multiplying 100%

0.03x100%=3%

Hope this is the brainliest answer.

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dedylja [7]

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3 years ago

How to solve how many 3/4s are in 2 with multiplication

ASHA 777 [7]

Answer:

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