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Firlakuza [10]
2 years ago
7

How to write a relative frequency

Mathematics
2 answers:
Tpy6a [65]2 years ago
3 0

Answer:

To find a relative frequency you need to divide the total number of x in the frequency to the total number. This can be represented as a fraction, decimal,  or percent.

Step-by-step explanation:

For example,

The ball landed 3 times out of 40.

3/40 = 7.5%

Elodia [21]2 years ago
3 0

Step-by-step explanation:

To find the relative frequencies, divide each frequency by the total number of students in the sample–in this case, 20. Relative frequencies can be written as fractions, percents, or decimals. Cumulative relative frequency is the accumulation of the previous relative frequencies.

Example: Your team has won 9 games from a total of 12 games played: the Frequency of winning is 9. the Relative Frequency of winning is 9/12 = 75%

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The ratio of Wei Ling's age to Wei Xuan's age 5 years ago was 2: 5. In 9 years
Archy [21]

Answer:

15 years old

Step-by-step explanation:

Start by defining the variables that we are going to use throughout our working:

Let the current age of Wei Ling and Wei Xuan be L and X years old respectively.

Next, form equations using the given information.

<u>5 years </u><u>ago</u>

Wei Ling: (L -5) years old

Wei Xuan: (X -5) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan's is 2: 5,

\frac{ L - 5}{X - 5}  =  \frac{2}{5}

Cross multiply:

2(X -5)= 5(L -5)

Expand:

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<u>9 years time</u>

Wei Ling: (L +9) years old

Wei Xuan: (X +9) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan is 3: 4,

\frac{L + 9}{X + 9}  =  \frac{3}{4}

Cross multiply:

3(X +9)= 4(L +9)

Expand:

3X +27= 4L +36

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3X= 4L +9 -----(2)

Let's solve using the elimination method.

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(3) -(4):

6X -6X= 15L -45 -(8L +18)

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Substitute L= 9 into (1):

2X= 5(9) -15

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2X= 30

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Thus, Wei Xuan is 15 years old now.

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