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Nostrana [21]
2 years ago
10

63 POINT!!!!! GUYS, I NEED HELP WITH PLSSSSS NO CHEAT THANK YOU!!

Mathematics
1 answer:
nikdorinn [45]2 years ago
6 0

Answer:

  236

Step-by-step explanation:

We assume the cost is a linear function of the number of lessons. That means the slope is the same everywhere.

Let (lessons, cost) = (x, y). We have (4, 84), (8, 160), (12, y3).

  (y2 -y1)/(x2 -x1) = (y3 -y2)/(x3 -x2)

  (160 -84)/(8 -4) = (y3 -160)/(12 -8)

  76 = y3 -160

  y3 = 160 +76 = 236

The cost will be $236 for 12 lessons.

__

The cost function is ...

  y = 19x +8 . . . . for x lessons

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For which rational expression is -5 an excluded value of x?
spayn [35]

Ration expressions cause excluded values wherever the denominator equals zero.

So, for any expression like

h(x)=\dfrac{f(x)}{g(x)}

-5 is an excluded value if g(-5)=0

For example, the simplest one would be

h(x) = \dfrac{1}{x+5}

In fact, if you try to evaluate this function at -5, you'd have

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7 0
3 years ago
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Cloud [144]

The first 5 terms in an arithmetic sequence is 4,2,0,-2,-4

Explanation:

The general form of an arithmetic sequence is

a(n)=a+(n-1)d

where a denotes the first term of the sequence, d denotes the common difference.

Here a = 4 and d = -2

To determine the consecutive terms of the sequence, let us substitute the values for n.

To find the second term, substitute n = 2 in the formula a(n)=a+(n-1)d

a(2)=4+(2-1)(-2)

Simplifying,

a(2)=4-2=2

Similarly,

For n = 3,

a(3)=4+(2)(-2)=0

For n = 4,

a(4)=4+(4-1)(-2)\\a(4)=4+(3)(-2)\\a(4)=4-6\\a(4)=-2

For n = 5,

a(5)=4+(5-1)(-2)\\a(5)=4+(4)(-2)\\a(5)=4-8\\a(5)=-4

Thus, the first 5 terms of the arithmetic sequence is 4,2,0,-2,-4

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According to Wine-Searcher, wine critics generally use a wine-scoring scale to communicate their opinions on the relative qualit
Romashka-Z-Leto [24]

Answer:

a

\= x  =  82

b

s =  9.64

Step-by-step explanation:

From the question we are told that

    The data is  87  91  86  82  72  91   60  77  80  79  83  96

Generally the point estimate for the mean is mathematically represented as

    \= x  =  \frac{\sum  x_i }{n}

=>  \= x  =  \frac{87 +91 + 86 + \cdots  + 96}{12}

=>    \= x  =  82

Generally the point estimate for the standard deviation  is mathematically represented as

      s =  \sqrt{\frac{ \sum ( x_i  - \= x )^2 }{ n -1 } }

=>     s =  \sqrt{\frac{ ( 87 - 82  )^2 +( 91 - 82  )^2 + \cdots + ( 96 - 82  )^2  }{ 12 -1 } }

=>     s =  9.64

8 0
3 years ago
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