I'm sorry I need the points lol anyways I hope you got the answer to it
Answer:
The given line segment has a midpoint at (−1, −2).
On a coordinate plane, a line goes through (negative 5, negative 3), (negative 1, negative 2), and (3, negative 1).
What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?
y = −4x − 4
y = −4x − 6
y = One-fourthx – 4
y = One-fourthx – 6
y = Three-halvesx + 1
Answer:
h'(1)=0
Step-by-step explanation:
We use the definition of the derivative of a quotient:
If
, then:
![h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}](https://tex.z-dn.net/?f=h%27%28x%29%3D%5Cfrac%7Bf%27%28x%29%2Ag%28x%29-f%28x%29%2Ag%27%28x%29%7D%7B%28g%28x%29%29%5E2%7D)
Since in our case we want the derivative of
at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:
![h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}](https://tex.z-dn.net/?f=h%27%281%29%3D%5Cfrac%7Bf%27%281%29%2Ag%281%29-f%281%29%2Ag%27%281%29%7D%7B%28g%281%29%29%5E2%7D)
which, by replacing with the given numerical values:
![f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3](https://tex.z-dn.net/?f=f%281%29%20%3D4%5C%5Cg%281%29%3D3%5C%5Cf%27%281%29%3D-4%5C%5Cg%27%281%29%3D-3)
becomes:
![h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0](https://tex.z-dn.net/?f=h%27%281%29%3D%5Cfrac%7Bf%27%281%29%2Ag%281%29-f%281%29%2Ag%27%281%29%7D%7B%28g%281%29%29%5E2%7D%3D%5C%5C%3D%5Cfrac%7B-4%2A3-4%2A%28-3%29%7D%7B%283%29%5E2%7D%3D%5Cfrac%7B-12%2B12%7D%7B9%7D%20%3D%5Cfrac%7B0%7D%7B9%7D%20%3D0)
Answer:
There is 7/15 left in the bag
Step-by-step explanation:
So, you need to find a common denominator between 3 and 5 which is 15
multiply the numerator and the denominator by 3 in 1/5. Then, multiply the numerator and the denominator by 5 in 1/3.
1/3*5=5/15
1/5*3=3/15
Add them together.
5/15+3/15=8/15
Lastly, subtract 15/15 by 8/15
15/15-8/15=7/15
Answer:
4f + 6g -5
Step-by-step explanation:
4f - 3 +2g- - 4g + 2
4f - 3+ 2g + 4g - 2
4f -3-2 +2g +4g
4f -5 + 6g
4f + 6g -5