Question

The diagonals of a parallelogram ABCD intersect at O.find ar(AOB),if ar(ABCD)is 44cm^2

Answer 1

Answer:

$11\text{ cm}^2$

Step-by-step explanation:

Given: In a parallelogram ABCD, diagonals intersect at O and ar(ABCD) is $44 \text{cm}^2$.

We need to find the area of triangle AOB.

We know that each diagonal divide the parallelogram in two equal parts and diagonals bisect each other.

It means both diagonals divide the parallelogram in 4 equal parts.

$ar(AOB)=\dfrac{1}{4}\times ar(ABCD)$

$ar(AOB)=\dfrac{1}{4}\times 44$

$ar(AOB)=11$

Hence, the values of ar(AOB) is $11\text{ cm}^2$.