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3 years ago

Find the area of the shaded portion in the square.

Mathematics

2 answers:

ozzi3 years ago

6 0

The answer is:

A = 8 - 2π

choli [55]3 years ago

4 0

Hello,
Please, see the attached file.
Thanks.

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This isn't really a school-related question.It's more of a conflict I have with my self. So: I have a friend that constantly cop

ycow [4]

Well to be honest, you need to straight forward to her and tell her that you do not appreciate her copying you and tell her you dont want to be rude or anything, but this needs to stop.

8 0

3 years ago

HURRYYYYY PLEASEEEEE Find the area of the circle. Use 3.14 for p.

scZoUnD [109]

Answer: B

Step-by-step explanation:

6 0

3 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago

A phone company offers two monthly plans. Plan A costs $17 plus an additional $0.09 for each minute of calls. Plan B costs $22 p

Varvara68 [4.7K]

Answer: $53

Step-by-step explanation:

17+ .09m = 9 + .11m

8 = .02m

m = 8/.02= 400 minutes for the two plans to cost the same

9+.11(400) = 9+ 44 = $53 when they cost the same

17+.09(400) = 17 +36 = $53

Please mark brainliest if it helped :)

8 0

3 years ago

Which are the solutions of x2 = 10x + 1?

padilas [110]

Answer:

we have

Complete the square. Remember to balance the equation by adding the same constants to each side

Rewrite as perfect squares

Square Root both sides

substitute

therefore

the answer is

the solutions are

Click to let others know, how helpful is it

RStep-by-step explanation:

6 0

3 years ago