The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
The answer is false. Hope this helps
It's important so that they know exactly where the disease started. Knowing who patient zero is helps them to identify who that person interacted with. From there, they can determine where the disease spread to. This will aid them in stopping the disease before it spreads any further.
The answer is B.) animals at the end of the food chain would not get enough food to stay alive.
