Answer:
The answer is <u>1.25</u>.
Step-by-step explanation:
<h3><u>Solution</u> :</h3>

According to the bodmas rule. Firstly, solving division



Now, using law of exponent rule to evaluate 2‐¹




According to bodmas rule. Solving multiplication.





Now, according to bodmas rule. Solving addition.


Hence, the answer is 1.25.

<h3><u>Learn More</u> :</h3>
✧ Algebraic identities :
⠀⇢ (a+b)²+(a-b)² = 2a²+2b²
⠀⇢ (a+b)²-(a-b)² = 4ab
⠀⇢ (a+b)(a -b) = a²-b²
⠀⇢ (a+b+c)² = a²+b²+c²+2ab+2bc+2ca
⠀⇢ (a-b)³ = a³-b³-3ab(a-b)
⠀⇢ (a³+b³) = (a+b)(a²-ab+b²)
⠀⇢ a²+b² = (a+b)²-2ab
⠀⇢ a³-b³ = (a-b)(a²+ab +b²)
⠀⇢ If a + b + c = 0 then a³ + b³ + c³ = 3abc
✧ BODMAS :
↝ BODMAS rule is an acronym used to remember the order of operations to be followed while solving expressions in mathematics.
It stands for :-
⠀ »» B - Brackets,
⠀ »» O - Order of powers or roots,
⠀ »» D - Division,
⠀ »» M - Multiplication
⠀ »» A - Addition
⠀ »» S - Subtraction.
↝ It means that expressions having multiple operators need to be simplified from left to right in this order only.
✧ BODMAS RULE :
↝ First, we solve brackets, then powers or roots,then division or multiplication (whatever comes first from the left side of the expression), and then at last subtraction or addition.
⠀ ↠ Addition (+)
⠀ ↠ Subtraction (-)
⠀ ↠ Multiplication (×)
⠀ ↠ Division (÷)
⠀ ↠ Brackets ( )
✧ EXPONENT :
↝ The exponent of a number says how many times to use the number in a multiplication.
✧ LAW OF EXPONENT :
The important laws of exponents are given below:
⠀ ➠ 
⠀ ➠ 
⠀ ➠ 
⠀ ➠ 
⠀ ➠ 
⠀ ➠ 
⠀ ➠ ![{\rm{{a}^{\frac{1}{n} } = \sqrt[n]{a}}}](https://tex.z-dn.net/?f=%7B%5Crm%7B%7Ba%7D%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%7D%7D%7D)
<u>▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬</u>