Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
The only solution I see is for x=0
Step-by-step explanation:
y=8x+2
y=-8x+2
y=y so substitute:
8X+2=-8X+2
Subtract 2 from each side
8X=-8X
divide each side by 8
x=-x
The only solution I see is for x=0
Answer:
Angle 1 = 46°
Angle 2 = 44°
Step-by-step explanation:
Given:
Angle 1 = (4x - 2)°
Angle 2 = (3x + 8)°
Angle 3 = 90°
Find:
All acute angle
Computation:
Using angle sum property
Angle 1 + Angle 1 + Angle 1 = 180°
(4x - 2)° + (3x + 8)° + 90° = 180°
7x + 6 = 90
7x = 84
x = 12°
So,
Angle 1 = (4x - 2)° = 4(12) - 2 = 46°
Angle 2 = (3x + 8)° = 3(12) + 8 = 44°