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givi [52]
2 years ago
12

PLS HELP BEST ANSWER=BRAINLIEST

Mathematics
2 answers:
8_murik_8 [283]2 years ago
5 0

Answer:

a-2=a-2

Step-by-step explanation:

Here it is, you just have to notice that the numerator has common factors alternated. You will then collect the same parentheses and simplify with the denominator.

Sliva [168]2 years ago
3 0

Answer:

Step-by-step explanation:

Parentheses are missing in your problem statement if you intend to simplify ...

  \dfrac{3a^2-ac+2c-6a}{3a-c}\\\\=\dfrac{a(3a-c) -2(3a-c)}{3a-c}\qquad\text{factor pairs of terms}\\\\=\dfrac{(a-2)(3a-c)}{(3a-c)}\\\\=\boxed{a-2}\qquad\text{cancel common factors}

The "steps" are ...

  • factor numerator (and denominator, if necessary)
  • cancel common factors
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The answer i’m on a timer
8_murik_8 [283]

Answer:

D. Down 5, Left 2

Step-by-step explanation:

-5 on the outside means it will go down 5.

+2 directly grouped with the variable means it will do the opposite, so it goes left 2.

7 0
3 years ago
Which point on the number line represents the product of 4 and -2.
Iteru [2.4K]

Answer:

A: -8

Step-by-step explanation:

4 * -2 is -8, and A is on that point.

8 0
3 years ago
52:44
bagirrra123 [75]

Answer:

1          

Step-by-step explanation:

8 0
3 years ago
Its all one big question
Verdich [7]

Answer:

see explanation

Step-by-step explanation:

h(x) + k(x) = x² + 1 + x - 2 = x² + x - 1

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

h(x) - k(x) = x² + 1 - (x - 2) = x² + 1 - x + 2 = x² -x + 3

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

3h(2) + 2k(3) = (3 × 5) + (2 × 1) = 15 + 2 = 17


7 0
3 years ago
Read 2 more answers
Explain how to determine if the two expressions are equivalent using x = 6 and x = 2.
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<span>Two algebraic expressions are said to be equivalent if their values obtained by substituting the values of the variables are same.</span>
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