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2 years ago

In a math class with 28 students, a test was given the same day that an assignment

Mathematics

1 answer:

Kipish [7]2 years ago

7 0

Answer:

Probability that a student who passed the test did not complete the homework = 0.07

Step-by-step explanation:

Given:

Total number of students = 28

Number of students who passed the test = 18

Number of students who completed the assignment = 23

Number of students who passed the test and also completed the assignment = 16

To find: probability that a student who passed the test did not complete the homework

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favorable outcomes/total number of outcomes

Let A denotes the event that students passed the test and B denotes the event that students completed the assignment

P(A only) = $P(A)-P(A\cap B)$

Here,

$P(A)=\frac{18}{28}\,,\,P(A\cap B)=\frac{16}{28}$

So,

$P(A\,\,only)=\frac{18}{28}-\frac{16}{28}=\frac{2}{28}=\frac{1}{14}=0.07$

Therefore,

probability that a student who passed the test did not complete the homework = 0.07

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Answer:

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2 years ago

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3 years ago

Read 2 more answers

Given lines p and q are parallel, find the value of x that makes each diagram true.

Klio2033 [76]

Answer: for a the answer is 140° and for b x=25°

Step-by-step explanation:

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3 years ago

A square has an area of 4 ft^2 what is the lenght of each side

sergiy2304 [10]

area of square = 4ft²

a s area of square = length×lenght

let lenght =x

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x²= 4ft²

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2 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

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3 years ago