If she is driving at 30 miles a hour it takes two minutes to cover a mile 60 divided by 30
if she is driving at 2 minutes a mile and is going 24 miles it will take 48 minutes
2*24 =48
solution she is a slow driver she needs to pick up the pace or she will be 3 minutes late to work
45-48=-3
Answer:
x = 5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
4x - 1 = 7x - 16
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract 4x on both sides: -1 = 3x - 16
- Add 16 to both sides: 15 = 3x
- Divide 3 on both sides: 5 = x
- Rewrite: x = 5
<u>Step 3: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in <em>x</em>: 4(5) - 1 = 7(5) - 16
- Multiply: 20 - 1 = 35 - 16
- Subtract: 19 = 19
Here we see that 19 does indeed equal 19.
∴ x = 5 is a solution to the equation.
Answer:
The average value of the function on the given interval 6.5.
Step-by-step explanation:
Consider the given function is

We need to find the average value of the function on the given interval [1,13].


The average value of the function f(x) on [a,b] is

Average value of the function on the given interval [1,13] is

![Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7Bx%5E2%7D%7B2%7D-0.5x%5D%5E%7B13%7D_%7B1%7D)
![Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7B%2813%29%5E2%7D%7B2%7D-0.5%2813%29-%28%5Cdfrac%7B%281%29%5E2%7D%7B2%7D-0.5%281%29%29%5D)
![Average=\dfrac{1}{12}[78-0]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B78-0%5D)

Therefore, the average value of the function on the given interval 6.5.
<u></u>You would add 54+42+153=249 to find the total amount of customers from the previous week. Then you would divide 54/249= 0.2168 to find the amount of customers that used cash to total customers. The closest fraction would be about 1/5.