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AURORKA [14]
3 years ago
6

Dilate triangle ABC by a factor of 2 around point A. What are the coordinates of B Q1 (1,0) Q2 (1,-1) Q3 (1,-2) Q4 (2,-4)

Mathematics
2 answers:
kkurt [141]3 years ago
8 0

Answer:

Option 3: (1,-2)

Step-by-step explanation:

From the given figure it is clear that the vertices of triangle ABC are A(1,4), B(1,1), C(4,1).

If a figure dilated by the factor k and the center of dilation is point (a,b), then the rule of dilation is

(x,y)\rightarrow (k(x-a)+a,k(y-b)+b)

The figure ABC dilated by the factor 2 and the center of dilation is point A(1,4).

(x,y)\rightarrow (2(x-1)+1,2(y-4)+4)

(x,y)\rightarrow (2x-2+1,2y-8+4)

(x,y)\rightarrow (2x-1,2y-4)

The coordinates of B after dilation are

B(1,1)\rightarrow B'(2(1)-1,2(1)-4)

B(1,1)\rightarrow B'(1,-2)

The coordinates of B after dilation are (1,-2).

Therefore, the correct option is 3.

GuDViN [60]3 years ago
4 0
The answer would be Q3 (1,-2)
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The distance between B and C
alina1380 [7]

Answer:

The answer is

<h2>\sqrt{13}  \:  \: or \:  \: 3.6055 \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{( {x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

B ( 3 , 1 ) and C( 6 , 3)

The distance between them is

|BC|  =  \sqrt{( {3 - 6})^{2}  +  ({1 - 3})^{2} }  \\  =  \sqrt{ ({ - 3})^{2}  + ( { - 2})^{2} }  \\  =  \sqrt{9 + 4}

We have the final answer as

\sqrt{13}  \:  \: or \:  \: 3.6055 \:  \: units

Hope this helps you

5 0
3 years ago
If you place a 20 ft ladder 4ft from the base of the wall. How high up will it reach? Round answer to the nearest tenth
xeze [42]

Answer:

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Step-by-step explanation:

Given that,

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We need to find the height of the reach. Let it is P.

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bixtya [17]

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xxTIMURxx [149]

Let

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5 0
3 years ago
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SOVA2 [1]

the surface area of the above triangular prism is 156 square inches.

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8 0
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