Given: l | | m m∠4 = 105° and m∠6 = 50°. m∠2 = 50° 55° 75°

Find the values of f(x) = 8x²-1 for the domain values {-2,5} (input answers from least to greatest}

Whitepunk [10]

Answer:

So i just used the calculator to help me find the two co exisiting lines and then worked my way up to find the nearest decimal to fit the equation for the missing parablar length which was parallel to find the cointerior angle which lead me to get a decimal number involving an ordinary form number.

7 0

1 year ago

Which ones are polynomials? Plz hurry

Gekata [30.6K]

Answer:

that don't matter just the pre test if u get a good grade on a pre test you don't got ot do the lesson.

Step-by-step explanation:

7 0

3 years ago

This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is

BaLLatris [955]

Answer:

$\frac{r}{3\pi h+r}$

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

$A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}$

Now, area of 2 cylinders would be the formula:

$A_{cyl}=2*(\pi r^2 h)=2\pi r^2 h$

So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm divided by A_total.

Shown below:

$\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}$

We simplify further:

$\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}$