Question

5x^2-7x+1=0 solve please

Answer 1

Answer:

Look below

Step-by-step explanation:

Answer 2

Answer:

$x=\frac{7+\sqrt{29}}{10},\:x=\frac{7-\sqrt{29}}{10}$

Step-by-step explanation:

$5x^2-7x+1=0$

Solving with the quadratic formula:

$x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\cdot \:5\cdot \:1}}{2\cdot \:5}$

$x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{29}}{2\cdot \:5}$

$x_1=\frac{-\left(-7\right)+\sqrt{29}}{2\cdot \:5},\:x_2=\frac{-\left(-7\right)-\sqrt{29}}{2\cdot \:5}$

$x=\frac{7+\sqrt{29}}{10},\:x=\frac{7-\sqrt{29}}{10}$