Check the picture below on the left-side.
we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.
now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.
so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

![\bf \textit{area of a segment of a circle}\\\\ A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta ) \right] \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ ------\\ r=6\\ \theta =120 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20segment%20of%20a%20circle%7D%5C%5C%5C%5C%0AA_y%3D%5Ccfrac%7Br%5E2%7D%7B2%7D%5Cleft%5B%5Ccfrac%7B%5Cpi%20%5Ctheta%20%7D%7B180%7D~-~sin%28%5Ctheta%20%29%20%20%5Cright%5D%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0A%5Ctheta%20%3Dangle~in%5C%5C%0A%5Cqquad%20degrees%5C%5C%0A------%5C%5C%0Ar%3D6%5C%5C%0A%5Ctheta%20%3D120%0A%5Cend%7Bcases%7D)
It would be 4/15 is greater.
4/15 = 26% wrong
3/10 = 30% wrong
Answer:
the new ratio milk/water is 14:6 or 7:3
Step-by-step explanation:
milk/water=5/3
milk +water=5+3=8
ratio of milk=5/8 and ratio of water=3/8
if 4 liter removed from mixture then: 20=4= 16 liter
the amount of milk in 16 liter=16*5/8=10 liter of milk
the amount of water in 16 liter=16*3/8= 6 liter
add 4 liter of milk to the mixture: 10+4=14 liter of milk and 6 liter of water
the new ratio milk/water is 14:6 or 7:3
Answer:

It's change of subject. :)
Answer:
60 millas por hora.
Step-by-step explanation:
Dado que un taxi viaja a una velocidad de 48 mph para llegar a un destino en 2 horas y media, para determinar cuál seria su velocidad si se tarda dos horas para llegar se debe realizar el siguiente cálculo:
48 x 2.5 = 120
120 / 2 = X
60 = X
Así, su velocidad, si se tardase dos horas en llegar, sería de 60 millas por hora.