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Andru [333]
3 years ago
15

This math promblem!!!!

Mathematics
2 answers:
fiasKO [112]3 years ago
6 0
1. You convert all the numbers into decimals.
   a. For 8 1/9 you multiply 8x9 and add the numerator which in this case is one, so the equation would be 8x9=72     then 72+1= 73
   b. For 81/10 I used a calculator for accuracy and I just divided 81 by 10 because the fraction line can also be used as a division sign. For this I got 8.1
2. Now I looked at all the numbers I had including the fractions I converted to decimals... 8.115, 8.55, 73, and 8.1
3. Lastly, I put the numbers in order from least to greatest: 8.1, 8.115, 8.55, and 73
4. In order to figure out which one is the smallest and largest, I just added zeros on the end of the numbers so they would all be the same: 8.1-->8.100, 8.115 I kept the same because it already had 3 decimal places, 8.55--> 8.550, and 73--> 73.000
5. Then i could tell which number was the largest by the decimal place numbers.
**Hope this was helpful... It's kind of hard to explain online but hopefully you have a better understanding of how to do it!**
steposvetlana [31]3 years ago
3 0

Answer:

sammytime is correct

Step-by-step explanation:

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8. myles had 103 coins in a jar - all nickels, dimes, and quarters. if the total value of the coins is $15
Ivanshal [37]

If the total value of the coins is $15. The number of each type of coin is: 31 quarters, 72 dimes.

<h3>Number of each type of coin</h3>

Let D = number of dimes

Let Q = the number of quarters

Equations

d + q = 103

0.10d + 0.25q = 15  

d = 103 -q

0.10(103 -q) + 0.25q = 15

10.3 - 0.10q + 0.25q = 15

0.15q = 4.7

q=4.7/0.15

q=31 quarters

Substitute q into second equation

D+31=103

D=72 dimes

Therefore the number of each type of coin is: 31 quarters, 72 dimes.

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Answer:

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