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Talja [164]
1 year ago
14

The distance between two cities is 145 miles. A truck can cover this distance in 2. 5 hours. A car is 1. 5 times as fast as the

truck. How long does it take them to meet, if they start moving towards each other simultaneously?.
Mathematics
1 answer:
Sophie [7]1 year ago
8 0

The relative speed of the car to the truck while moving towards each other is the sum of the speed of both vehicles.

  • The time it takes them to meet is <u>1 hour</u>

Reasons:

The distance between the cities, d = 145 miles

The time it takes a truck to cover the distance = 2.5 hours

The speed of the car = 1.5 × Th speed of the truck

Required:

The time it takes them to meet if they are moving towards each other.

Solution:

  • \displaystyle Speed = \mathbf{ \frac{Distance}{Time}}

\displaystyle Speed \ of \ the \ truck, \ v_{truck} = \frac{145 \ miles}{2.5 \ hours} = \mathbf{58 \ mph}

Therefore;

The speed of the car, v_{car} = 1.5 × 58 mph = 87 mph

At the time<em>, t</em>, the truck and the car meet, we have;

\mathbf{v_{car} \times t + v_{truck} \times t = d}

Which gives;

87 × t + 58 × t = 145

\displaystyle t = \mathbf{\frac{145}{87 + 58}} = 1

  • The time it takes them to meet, <em>t</em> = <u>1 hour</u>

Learn more about distance, time and speed here:

brainly.com/question/17609639

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Is -5 greater than -9
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Step-by-step explanation:


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How do you solve this?
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There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

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3 years ago
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