Answer:
a) C = 250 + 1.25n
b) 1800
c) 300
Step-by-step explanation:
a) To write the equation for these problems, let's establish the constant, $250, since we are given that $250 is a FIXED cost, meaning no matter how many brochures we print, we will have to pay $250. Then, we have to pay $1.25 for each brochure, so for n amount of brochures, so we have 1.25*n. Putting it together, we have the fixed cost + the cost of producing n brochures, C = 250 + 1.25C
b) The cost of printing 2500 brochures can be found by pluggin number into the equation above. C = 250 + 1.25*2500 = $1800
c) This is the opposite question, since 625 is the final cost, we plug it into the final cost, 625 = 250 + 1.25*n. Solving gives n = 300
To solve this question, we simply need to divide the total amount of students by 8% to find out how many students were absent and how many were present.
However, we can't simply multiply it by 8%, so we need to turn that into a decimal.
8% - 0.08
<em>Multiply:</em>
<em>355 x 0.08</em>
<em>= 28.4</em>
<em>Round:</em>
<em>28 kids were absent</em>
<em>Subtract:</em>
<em>355 - 28</em>
<em>= 327</em>
<em />
<em>This means that </em><em>28 kids were absent</em><em>, and </em><em>327 kids were present</em><em>.</em><em> </em>
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Answer:
x = 0.666(Repeating)
Step-by-step explanation:
4x+1=5
Subtract 1 from both sides
4x=6
Divide both sides by 4
x = 0.666(Repeating)
The sum of the m numbers divided by m (which is the average) equals n^2. Then, the sum of the m numbers equals mn^2.
The sum of the n numbers divided by n (which is the average) equals m^2. Then, the sum of the n numbers equals nm^2.
The average of m+n numbers which is the sum of the m numbers plus the sum of the n numbers divided by (m+n) equals (mn^2+nm^2)/(m+n). This is mn(n+m)/(m+n). Then the factor (m+n) can be ruled out and the result is mn.
Answer:
There are 32 outcomes that are possible
Step-by-step explanation:
