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Wewaii [24]
2 years ago
13

An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $6600 and his st

ock in Company B was worth $3500. The stock in Company A has increased 7% since last year and the stock in Company B has increased 1%. What was the total percentage increase in the investor's stock account? Round your answer to the nearest tenth (if necessary). pls asap
Mathematics
1 answer:
Nonamiya [84]2 years ago
7 0

Answer:

4.9%

Step-by-step explanation:

6600 * 107/100 = 66*107 = 7062.

3500 * 101/100 = 35x101 = 3535

7062+3535=10597. Original worth: 10100

10597-10100 = 497

497/10100 = 0.0492079208, or 4.92%, rounds to 4.9%

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yaroslaw [1]

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Note the equal sign, subtract c from both sides:

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Note the equal sign, divide F from both sides:

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4) 3x - q = p

Note the equal sign, first, add q to both sides:

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3 0
3 years ago
BRAINLIET TO THE FIRST.....AND PLZZ HURRY.....
fgiga [73]

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Since this is a right cone, the height is given as 8.5 and the radius is 4.

V = 1/3 x pi x 4^2 x 8.5

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V = 1/3 x pi x 136

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Hope this helps!

5 0
2 years ago
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Drupady [299]
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3 years ago
Wht is -3(2x-1)+8=15
Svetllana [295]

Answer:

x=-\frac{2}{3}

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Which function has a constant additive rate of change of 14
Maurinko [17]

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Full question:

Is in the image uploaded.

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