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3 years ago

Find the value of x.

Mathematics

1 answer:

Artemon [7]3 years ago

6 0

${5}^{2} + {x}^{2} = {8}^{2}$

$25 + {x}^{2} = 64$

Subtract both sides 25

$25 - 25 + {x}^{2} = 64 - 25$

${x}^{2} = 39$

Thus :

$x = \sqrt{39}$

$x = 6.245$

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Read 2 more answers

In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each

Rudiy27

Answer:

$N(t) = 972(1.015)^{t}$

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

$N(t) = N(0)(1+r)^{t}$

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that $N(0) = 972$

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that $r = 0.015$

Then

$N(t) = N(0)(1+r)^{t}$

$N(t) = 972(1+0.015)^{t}$

$N(t) = 972(1.015)^{t}$

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

$N(t) = 972(1.015)^{t}$

$N(12) = 972(1.015)^{12}$

$N(12) = 1162$

The number of students enrolled in 2014 is 1162.

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