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tester [92]
2 years ago
13

Can anybody help with this?

Mathematics
1 answer:
pickupchik [31]2 years ago
5 0
I think it’s the last one
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Find sin 2x,cos2x and tan2x,if tanx=-(3)/(4)and x terminates in quadrant IV
Montano1993 [528]

Answer:PLEASE HELP ME

Step-by-step explanation:

here can you guys please help me with this question.

I have been asking help from so many people but no one is nice enough to give it so im hoping that anyone over here can help me. this is the problem

Carl is standing at the base of a zip line which is 400 ft away from the base of the building that is connected to the top of a building. Standing 5.5 ft tall, he looks up to the top of the building at an angle of elevation of 25 degrees. A weight is released and travels down the zip line to his feet. How far did the weight travel? Round to nearest 10th of a foot and do not use units in your answer.

Please show work

7 0
3 years ago
a family's monthly utility costs are phone 200 electric 100 Cable TV 100 water and gas 50 internet 50 by eliminating cable by wh
AleksandrR [38]

Answer:

500

Step-by-step explanation:

I'm not sure

6 0
3 years ago
For which of the following decreasing functions f does (f−1)′(10)=−1/8
Oduvanchick [21]

Recall the inverse function theorem: if f(x) has an inverse, and if f(a) = b and a = f⁻¹(b), then

f⁻¹(f(x)) = x   ⇒   (f⁻¹)'(f(x)) • f'(x) = 1   ⇒   (f⁻¹)'(f(x)) = 1/f'(x)

⇒   (f⁻¹)'(b) = 1/f'(a)

Let b = 10. Then pick the function f(x) such that f(a) = 10 and f'(a) = -8 for some number a.

7 0
2 years ago
Find the GCF (Greatest Common Factor) of 64 and 144
valkas [14]

Answer: 16

Step-by-step explanation:

if we were to list all the factors of 64 and 144

64= 1,2,4,8,8,16,32,64

144= 1,2,3,4,6,8,9,12,12,16,18,24,36,48,72,144

therefore the GCF of 64 and 144 is 16

3 0
3 years ago
Read 2 more answers
Anna is planning a big birthday bash for her sixteenth birthday party and wants to invite as many people as possible but she has
Doss [256]
Im not an expert or anything, but i think for the innequality, i would say

6.50p + 100 \leqslant 500

as far as the amount of people she can invite, do 500-100=400 because of the setup fee, then, to find how many people she can invite. 400÷6.50 which leaves you with the highest amount of people she can invite without going over budget, as 61.
3 0
4 years ago
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