Answer: the probability that two accidents will occur during the (five-day) work week is 0.0758
Step-by-step explanation:
Given that;
injuries in textile mill occur at the rate of 0.1 per day; λ = 0.1
probability that two accidents will occur during the (five-day) work week = ?
T= 5
so, the average number of on the job injuries for five days will be;
λT = 0.1 × 5
= 0.5
now if X follows Poisson distribution, hemce
P( X=k ) = [e^-λT (λT)^k] / k!
so the probability that two (2) accidents will occur during the (five-day) work week will be;
P( X=k ) = [e^-0.5 (0.5)²] / 2!
= (0.6065 × 0.25) / 2
= 0.1516/ 2
= 0.0758
the probability that two accidents will occur during the (five-day) work week is 0.0758
Answer:
x=3
Step-by-step explanation:
6x-3
(6*3)-3
18-3
15
3x+6
(3*3)+6
9+6
15
5x
5*3
15
Answer:
4,000
Step-by-step explanation:
0.50x + 8.75 < = 16
0.50x < = 16 - 8.75
0.50x < = 7.25
x < = 7.25 / 0.50
x < = 14.5 <===
Multiply both variables individually by the multiplied variable (x)... and you find yourself with -fx + hx.... Remember to bring that negative integer along too or the answere that I have without a negative integer won't count... I hope this clarified your understanding and question. As always good spiruts
