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mel-nik [20]
3 years ago
6

Why doesn't the existence of a correlation always indicate a cause and effect relationship?

Mathematics
1 answer:
maxonik [38]3 years ago
4 0
Because correlation and causation are 2 different links
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María compró libros por internet y gastó un total de 97 cada libro costó 7 y pagó un total de 6 por el envío cuántos libros comp
Zigmanuir [339]
Ddfndnd dddd ddddd ddddd ddd
5 0
3 years ago
Describe the transformations from the parent function f(x)=x^2 to the function g(x+2)^2+5
jolli1 [7]

Answer:

The parent function is the simplest form of the type of function given.

g

(

x

)

=

x

2

The transformation being described is from  

g

(

x

)

=

x

2

to  

f

(

x

)

=

x

2

.

g

(

x

)

=

x

2

→

f

(

x

)

=

x

2

The horizontal shift depends on the value of  

h

. The horizontal shift is described as:

f

(

x

)

=

f

(

x

+

h

)

- The graph is shifted to the left  

h

units.

f

(

x

)

=

f

(

x

−

h

)

- The graph is shifted to the right  

h

units.

In this case,  

h

=

0

which means that the graph is not shifted to the left or right.

Horizontal Shift: None

The vertical shift depends on the value of  

k

. The vertical shift is described as:

f

(

x

)

=

f

(

x

)

+

k

- The graph is shifted up  

k

units.

f

(

x

)

=

f

(

x

)

−

k

- The graph is shifted down  

k

units.

In this case,  

k

=

0

which means that the graph is not shifted up or down.

Vertical Shift: None

The graph is reflected about the x-axis when  

f  (

x

)

=

−

f

(

x

)

.

Reflection about the x-axis: None

The graph is reflected about the y-axis when  

f

(

x

)

=

f

(

−

x

)

.

Reflection about the y-axis: None

Compressing and stretching depends on the value of  

a

.

When  

a

is greater than  

1

: Vertically stretched

When  

a

is between  

0

and  

1

: Vertically compressed

Vertical Compression or Stretch: None

Compare and list the transformations.

Parent Function:  

g

(

x

)

=

x

2

Horizontal Shift: None

Vertical Shift: None

Reflection about the x-axis: None

Reflection about the y-axis: None

Vertical Compression or Stretch: None

image of graph

5 0
3 years ago
Find values of a and b that make the following equality into identity:
adelina 88 [10]

Answer:

1. a=b=\dfrac{3}{4}

2. a=-3,\ b=3

Step-by-step explanation:

1. Given:

\dfrac{3x}{(x-2)(3x+2)}=\dfrac{a}{x-2}+\dfrac{b}{3x+2}

To find a and b, add two fractions in right side:

\dfrac{a}{x-2}+\dfrac{b}{3x+2}\\ \\=\dfrac{a(3x+2)+b(x-2)}{(x-2)(3x+2)}\\ \\=\dfrac{3ax+2a+bx-2b}{(x-2)(3x+2)}\\ \\=\dfrac{(3a+b)x+(2a-2b)}{(x-2)(3x+2)}

So,

\dfrac{3x}{(x-2)(3x+2)}=\dfrac{(3a+b)x+(2a-2b)}{(x-2)(3x+2)}

Two fractions with same denominators are equal when they have equal numerators, so

3x=(3a+b)x+(2a-2b)

Equate coefficients:

At\ x:\ \ 3=3a+b\\ \\At \ 1: 0=2a-2b

From the second equation:

a=b

Substitute it into the first equation:

3b+b=3\\ \\4b=3\\ \\b=\dfrac{3}{4}

Hence,

\dfrac{3x}{(x-2)(3x+2)}=\dfrac{\frac{3}{4}}{x-2}+\dfrac{\frac{3}{4}}{3x+2}

2. Given:

\dfrac{3}{x^2-5x+6}=\dfrac{a}{x-2}+\dfrac{b}{x-3}

Note that (x-2)(x-3)=x^2-3x-2x+6=x^2-5x+6

To find a and b, add two fractions in right side:

\dfrac{a}{x-2}+\dfrac{b}{x-3}\\ \\=\dfrac{a(x-3)+b(x-2)}{(x-2)(x-3)}\\ \\=\dfrac{ax-3a+bx-2b}{(x-2)(x-3)}\\ \\=\dfrac{(a+b)x+(-3a-2b)}{(x-2)(x-3)}

So,

\dfrac{3}{(x-2)(x-3)}=\dfrac{(a+b)x+(-3a-2b)}{(x-2)(x-3)}

Two fractions with same denominators are equal when they have equal numerators, so

3=(a+b)x+(-3a-2b)

Equate coefficients:

At\ x:\ \ 0=a+b\\ \\At \ 1: 3=-3a-2b

From the first equation:

a=-b

Substitute it into the second equation:

-3(-b)-2b=3\\ \\3b-2b=3\\ \\b=3\\ \\a=-3

Hence,

\dfrac{3}{x^2-5x+6}=\dfrac{-3}{x-2}+\dfrac{3}{x-3}

4 0
3 years ago
I can't find the area
Tema [17]
I am not sure but i think its 70m

hope this helps

4 0
3 years ago
Jill's employer has a co
Dimas [21]
Jill's employer has a co? What is the question to this mathematic equation i would like to know so i can pleasely help you
8 0
3 years ago
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