Well, remember we can't take the square root of a negative
so we see that we have

so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input

for y1
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7
Answer:
The amount depositied is less than or equal to the amount of money in his wallet.
Step-by-step explanation:
PLEASE GIVE mE BRA1NL1EST!!!
The graph would intercept at (0,-4) on the y-axis & at (5.3,0) on the x-axis. And the shaded region would be on the right side of the line on the graph.
The solution to the system of equations is x = 8, y = 4.
<h3>
How to write the system of equations?</h3>
First, let's define our variables as x and y.
"the sum of two numbers is twelve" is written as:
x + y = 12
"two times the first number minus three times the second number is four" is written as:
2x - 3y = 4
Then the system of equations is:
x + y = 12
2x - 3y = 4
<h3>How to solve it?</h3>
First, we isolate one of the variables in one equation, I will isolate x on the first one to get:
x = 12 - y
Now we replace this on the other equation, so we get:
2*(12 - y) - 3y = 4
Now we can solve this for y.
24 - 2y - 3y = 4
24 - 5y = 4
24 - 4 = 5y
20/5 = y = 4
Now we know the value of y, and:
x = 12 - y = 12 - 4 = 8
Then the solution of the system is:
x = 8, y = 4.
If you want to learn more about systems of equations, you can read:
brainly.com/question/13729904