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vlabodo [156]
3 years ago
8

Let x and y be the input and output of a measurement system, respectively. It is known that their relationship is 2 0.5 x =  .

(a) Calculate the sensitivity of this measurement, when x = 0, 1, 2, 5, and 10.
Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

At x = 0, Sensitivity = Not defined

At x = 1, Sensitivity = 3.2974

At x = 2, Sensitivity = 2.71825

At x = 5, Sensitivity = 4.8729

At x = 10, Sensitivity = 29.6826

Step-by-step explanation:

We are given the following in the question:

y = 2e^{0.5x}

where y is the output and x is the input of a system.

We define sensitivity as the ration of output to input.

\text{Sensitivity} = \displaystyle\frac{\text{Out-put}}{\text{In-put}} = \frac{y}{x}

At x  = 0

y = 2e^{0.5(0)} = 2\\\\\text{Senstivity} = \displaystyle\frac{2}{0} = \text{N.D}

At x = 1

y = 2e^{0.5(1)} =3.2974\\\\\text{Senstivity} = \displaystyle\frac{3.2974}{1} = 3.2974

At x = 2

y = 2e^{0.5(2)} =5.4365\\\\\text{Senstivity} = \displaystyle\frac{5.4365}{2} = 2.71825

At x = 5

y = 2e^{0.5(5)} =24.3649\\\\\text{Senstivity} = \displaystyle\frac{24.3649}{5} = 4.8729

At x = 10

y = 2e^{0.5(10)} =296.8263\\\\\text{Senstivity} = \displaystyle\frac{296.8263}{10} = 29.6826

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