Which is the y-intercept of the relationship represented in the table?

89 44 What is the value of v? V= o

mr Goodwill [35]

Step-by-step explanation:

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7 0

2 years ago

Help :( I need this :)

valina [46]

Answer:

you can put in any of the numbers that are already listed in the x values. You can put 5, 14, -1, and 23 because something can't be a function if x values repeat.

8 0

2 years ago

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago

, Hayley sold 20 tickets to the school play for a total of $225 early bird tickets were $10 and regular price tickets were $15 w

Lady_Fox [76]

Answer:

15 early tickets were sold and 5 regular tickets were sold.

Step-by-step explanation:

Let x be the number of early bird tickets sold and y be the number of regular tickets sold.

Total number of tickets sold = 20

Thus, we can write the equation,

$x + y = 20$

Cost of early bird ticket = $10

Cost of regular tickets = $15

Total cost = $225

Thus, we can write the equation,

$225 = 10x + 15y$

We solve the equation by elimination method by multiplying first equation by 10 and subtracting.

$10x + 15y-(10x+10y) = 225 - 200\\5y = 25\\\Rightarrow y=5\\x + 5 = 20\\\Rightarrow x = 15$

Thus, 15 early tickets were sold and 5 regular tickets were sold.

5 0

3 years ago

HELP ME OUT ASAP PLS 20POINTS IF U DO! On Friday, a bowling alley made $842.72 from lane rentals and $412.38 from the concession

ElenaW [278]

Answer:

$2611.05

Step-by-step explanation:

earnings = lane rentals + concessions

Friday:

earnings = $842.72 +412.38 = $1255.10

Saturday:

We assume "down by 1/8" means the value was 1 -1/8 = 7/8 that of the previous day. Likewise, "increased by 1/2" is assumed to mean the value was 1 + 1/2 = 3/2 that of the previous day.

earnings = 7/8×$842.72 + 3/2×412.38 = $1355.95

__

Then the total earnings for both days were ...

$1255.10 +$1355.95 = $2611.05

7 0

3 years ago

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