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barxatty [35]
3 years ago
15

Sam is renting one of two cars to go on a 300-mile trip. The first car can travel 75 miles on 5 gallons of gas. The second car c

an travel 240 miles on 20 gallons of gas. Each car costs the same to rent, and Sam wants to rent the car with the better gas mileage. Sam estimates that he will pay $49.42 for every 14 gallons of gas he has to buy. Which car should Sam rent, and how much money should Sam bring for gas? Explain your reasoning.
Mathematics
1 answer:
Doss [256]3 years ago
3 0

Solution:

The first car can travel 75 miles on 5 gallons of gas.

So  per mile gas consumed by car=\frac{5}{75}=\frac{1}{15} gallon

The second car can travel 240 miles on 20 gallons of gas.

So  per mile gas consumed by car=\frac{20}{240}=\frac{1}{12} gallon

It mean Sam should rent the First car.

Sam is renting one of two cars to go on a 300-mile trip.

So total number of gallons of gas required=\frac{1}{15}*300=20

Total cost of 20 gallons of gas =\frac{49.42}{14}*20= 70.6 dollar

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Answer:

66.6% decrease in distance

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Step-by-step explanation:

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Nikolay [14]

Answer:

3/2

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To get the scale factor you have to compare the sides.

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3 0
3 years ago
Felicia decided to purchase 2 points in order to lower her interest rate on her $149,000 mortgage. How much additional money doe
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Answer:

$2,980

Step-by-step explanation:

Mortgage points is a term used by a mortgage brokers and it is usually referred to the percentage of the loan amount.

From the given question:

Felicia decided to purchase 2 points in order to lower her interest rate on her $149,000 mortgage

the 2 points that Felicia purchased is equivalent to 2% i.e 0.02 points

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cost = points × loan amount

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= $2,980

4 0
3 years ago
Which inequality is true?
kipiarov [429]
3/4 is greater than 2/3 is the right one. Because 1/2 is more than 1/3. -1/4 is not less than -2/3, and -1 is not greater than 3/4s. I hope it helps
6 0
3 years ago
A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati
Marysya12 [62]
The 100(1-\alpha)\% confidence interval of a standard deviation is given by:

\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval, 

\chi^2_{1- \frac{\alpha}{2} }=43.773 \\  \\ \chi^2_{\frac{\alpha}{2} }=18.493

Therefore, the 90% confidence interval for the standard deviation is given by

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3 0
3 years ago
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