Hello, your answer would be (-5, 5)
1/6
Step-by-step explanation:
- According to the question, the right combination of 2 wires cut (out of the 4 wires ) will defuse the bomb. To find all the possible combinations we using the following formulae;
nCr = n! / r! * (n - r)!
⁴₂C = 4! / 2! * (4-2)!
⁴₂C = 24 / 2 * 2
⁴₂C = 6
- There are a possible 6 combinations
- Therefore for probability of cutting the right combination of 2 wires is 1/6
Learn More:
To learn more about combinations check out;
brainly.com/question/3374511
brainly.com/question/3901018
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The first if a twisted version of a Fibonacci sequence :P
If a1=1.2 and a2=2.3 and a(n)=a(n-1)+a(n-2)
a3=3.5, a4=5.8, a5=9.3
So the first five terms are: 1.2, 2.3, 3.5, 5.8, 9.3
The second is another modified Fibonacci sequence...
If a3=-5 and a4=3 then:
3=-5+a2, a2=8
-5=8+a1, a1=-13
a5=-5+3=-2
a6=-2+3=1
So the first six terms are -13, 8, -5, 3, -2, 1
Well
21-8= 13
63-21=42
42-21=21
13*2=26 t
There is 26 non woodwind instruments