In finding this value you average lower and upper bound
(0.6+0.82)/2 = 0.71
=0.71 estimated
margin of error = distance from estimate point lower/ upper bound
This interval will be twice margin error
(0.82-0.6)/2 = 0.11
How far is 0.82 from 0.71 ??
=0.11=11%
Since in this case we are
only using the variance of the sample and not the variance of the real population,
therefore we use the t statistic. The formula for the confidence interval is:
<span>CI = X ± t * s / sqrt(n) ---> 1</span>
Where,
X = the sample mean = 84
t = the t score which is
obtained in the standard distribution tables at 95% confidence level
s = sample variance = 12.25
n = number of samples = 49
From the table at 95%
confidence interval and degrees of freedom of 48 (DOF = n -1), the value of t
is around:
t = 1.68
Therefore substituting the
given values to equation 1:
CI = 84 ± 1.68 * 12.25 /
sqrt(49)
CI = 84 ± 2.94
CI = 81.06, 86.94
<span>Therefore at 95% confidence
level, the scores is from 81 to 87.</span>
Answer:
32 and 40
Step-by-step explanation:
Let's call the smaller number x. If the smaller number is x, the equation for this problem is 2x + 8 = 72
Equation:
2x + 8 = 72
2x = 64
x = 32
So now we know the smaller number is 32, so now add 8 and we get 40.
Therefore the 2 numbers are 32 and 40
Answer:
A. 3a-2=54
Step-by-step explanation:
3 x her age - the 2 year will equal 54
<h3><u>Part A</u></h3>
factor the common term 'y' and '-4'
collect into groups
<h3><u>Part B</u></h3>
middle term split
factor the common term '3x' and '-2'
collect into groups
simplify the following
