Answer: 1902.36
Step-by-step explanation:
When interest is compounded monthly , the formula to find the accumulated amount is
, where P = principal value , r = rate of interest , t = time.
As per given,
r= 24% = 0.24
P= $1500
t= 1 year
Put all value in formula , we get
Hence, he need to pay $1902.36.
<span>Don't forget S is measured in thousands of units so you are solving for :
100 < 74.5 + 43.75Sin(πt/6)
25.5 < 43.75Sin(πt/6)
Sin(πt/6) >25.5/43.75 = 0.582857
ASrcSin(πt/6) > 0.62224 radians
πt/6 > 0.62224
t > 6 x 0.62224/π = 1.1884 (4dp)
This initial value occurs when the sine value is increasing and it will reach its maximum value of 1 when Sin(πt/6) = Sinπ/2, that is when t = 3.
Consequently, monthly sales exceed 100,000 during the period between t = 1.1884 and 4.8116
[3 - 1.1884 = 1.8116 so the other extreme occurs at 3 + 1.8116]
Note : on the basis of these calculations, January is 0 ≤ t < 1 : February is 1 ≤ t < 2 :....May is 4 ≤ t < 5
So the period when sales exceed 100,000 occurs between Feb 6 and May 25 and annually thereafter.</span>
According to the probles represented above, there is addition of two angles which makes it totally clear. I am pretty sure that the answer with the actual reason of this task is the second option <span>B. Angle Addition Postulate, as you can see a couple of new angles in there :)
Regards!</span>
