All categories

2 years ago

Someone please help <33

Mathematics

1 answer:

Troyanec [42]2 years ago

7 0

Distribute

4x(2x^2-4x+5)-5x(2x+6)

8x^3-16x^2+20x-10x^3-30x

Combine Like Terms

8x^3-16x^2+20x-10x^3-30x

-2x^3-16^2+20x-30x

Combine like terms

-2x^3-16x^2 +20x-30x

-2x^3-16x^2-10x

Common factor

Factor by grouping

-2x^3 - 16x^2-10x

Find one factor

-2(x^3+8x^2+5x)

--------------

<h2>Your answer: -2x(5x^2+4x+5)</h2><h2>(Simplified = 10x^3 + 8x^2 + 10x)</h2>

You might be interested in

(x-1)2 + (y + 3)2 = 73<br> What is the center ?

Olenka [21]

Answer:

centre = (1, - 3 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 1)² + (y + 3)² = 73 ← is in standard form

with (h, k ) = (1, - 3 ) ← centre

3 0

2 years ago

Which number expresses 6.72 as a fraction in simplest form?

Dimas [21]

The number that expresses 6.72 as a fraction is simplest form is...

6.72= 168/25

5 0

3 years ago

How long does it take to travel 360 km at a constant speed of 12 km/h?

Law Incorporation [45]

Answer:

30 hours is the right answer

5 0

2 years ago

Please help, thanks thanks

Marysya12 [62]

Answer:

i think its 2 but im not sure

Step-by-step explanation:

sorry if im wrong

7 0

2 years ago

Read 2 more answers

PLEASE HELP ME IVE POSTED THIS 765678 AND STILL NO RESPONSE

Debora [2.8K]

Problem 1

<h3>Answer: 6.7</h3>

----------------

Work Shown:

The two points are $(x_1,y_1) = (1,-2)$ and $(x_2,y_2) = (4,4)$

Apply the distance formula to get the following

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\$

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer: 3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points $(x_1,y_1) = (3,1)$ and $(x_2,y_2) = (5,-2)$

The distance between them is...

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\$

This distance is approximate.

5 0

2 years ago