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polet [3.4K]
3 years ago
15

Which of the following relations represents a function? A. (2,3), (1,3), (3,3) B. (1,3), (2,3), (2,4) C. (1,3), (2,3), (1,4) D.

(2,2), (2,3), (2,1)
Mathematics
2 answers:
melamori03 [73]3 years ago
6 0
On a function groupset, you can't have the same X values, but you can have the same Y values. Example: If you had {(3,1) (5,1) (6,3)} it would be a function since no X values are the same.

On choice A., they all have the same Y value, but no X values are the same.
On choice B, (2,3) and (2,4) have the same X value.
On choice C, (1,3) and (1,4) have the same X value.
On choice D, they all have the same X value.

In short, your answer would be choice A, because no X values are the same.
insens350 [35]3 years ago
3 0
A function will not have ANY repeating x values....it can have repeating y values...just not the x ones

so ur function is : (2,3) ,(1,3), (3,3) ....u see how u have no repeating x values
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Answer:

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Step-by-step explanation:

(5³)⁹/5¹²

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Let R1 and R2 are the remainders when the polynomials x^3 + 2x^2 − 5ax − 7 and x^3 + ax^2 − 12x + 6 are divided by x + 1 and x −
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Answer:

2.44

Step-by-step explanation:

Given: x³ + 2x² - 5ax - 7      and  x³ + ax² - 12x + 6

Also, R1 + R2 = 6

in order to find the value of a:

Let p(x) = x³ + 2x² - 5ax - 7 and q(x) = x³ + ax² - 12x + 6

Using remainder theorem i.e if a polynomial p(x) is divisible by polynomial of form x - a then remainder is given by p(a).

Then,

R1 = p( -1 ) = (-1)³ + 2(-1)² - 5a(-1) - 7 = -1 + 2 + 5a - 7 = 5a - 6

R2 = q( 2 ) = 2³ + a(2)² - 12(2) + 6 = 8 + 4a - 24 + 6 = 4a - 10

Now,

R1 + R2 = 6

5a - 6 + 4a - 10 = 6

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Therefore, Value of a is 2.44

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