The first answer is the correct one
Answer:
The answer is 1.
Step-by-step explanation:
Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.
Answer:
(1,-1)
(7,12)
(5,-3)
Step-by-step explanation:
we know that
If a ordered pair is a solution of the inequality, then the ordered pair must satisfy the inequality
we have

Verify each case
case 1) we have
(1,-1)
substitute the value of x and the value of y in the inequality and then compare the results

----> is true
therefore
The ordered pair is a solution of the inequality
case 2) we have
(7,12)
substitute the value of x and the value of y in the inequality and then compare the results

----> is true
therefore
The ordered pair is a solution of the inequality
case 3) we have
(-6,-3)
substitute the value of x and the value of y in the inequality and then compare the results

----> is not true
therefore
The ordered pair is not a solution of the inequality
case 4) we have
(0,-2)
substitute the value of x and the value of y in the inequality and then compare the results

----> is not true
therefore
The ordered pair is not a solution of the inequality
case 5) we have
(5,-3)
substitute the value of x and the value of y in the inequality and then compare the results

----> is true
therefore
The ordered pair is a solution of the inequality