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hammer [34]
2 years ago
12

Someone help me with this question plzzz

Mathematics
1 answer:
asambeis [7]2 years ago
7 0

Answer:

Step-by-step explanation:

As per Janayda,

From the figure attached,

In ΔTRQ,

m∠TRQ + m∠RQT + m∠QTR = 180°

25° + m∠RQT + 35° = 180°

m∠RQT = 180° - 60°

m∠RQT = 120°

Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]

m∠PQT = 180° - m∠RQT

             = 180° - 120°

             = 60°

In right angled triangle TPQ,

m∠TPQ + m∠PQT + m∠PTQ = 180°

90° + 60° + m∠PTQ = 180°

m∠PTQ = 180° - 150°

             = 30°

Similarly, other angles can also be evaluated from the given information.

In ΔQTP and ΔNTP,

TP ≅ TP [Reflexive property]

NP ≅ PQ [Given]

ΔQTP ≅ ΔNTP [By LL postulate for congruence]

Therefore, Janayda is correct.

While Sirr is incorrect.

Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.

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All variables count as coefficients,  so they’d be 8m, k, and -16k

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The constants are just numbers on their own, or without a variable next to it. Here it’d be 10 and -4


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