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hammer [34]
3 years ago
12

Someone help me with this question plzzz

Mathematics
1 answer:
asambeis [7]3 years ago
7 0

Answer:

Step-by-step explanation:

As per Janayda,

From the figure attached,

In ΔTRQ,

m∠TRQ + m∠RQT + m∠QTR = 180°

25° + m∠RQT + 35° = 180°

m∠RQT = 180° - 60°

m∠RQT = 120°

Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]

m∠PQT = 180° - m∠RQT

             = 180° - 120°

             = 60°

In right angled triangle TPQ,

m∠TPQ + m∠PQT + m∠PTQ = 180°

90° + 60° + m∠PTQ = 180°

m∠PTQ = 180° - 150°

             = 30°

Similarly, other angles can also be evaluated from the given information.

In ΔQTP and ΔNTP,

TP ≅ TP [Reflexive property]

NP ≅ PQ [Given]

ΔQTP ≅ ΔNTP [By LL postulate for congruence]

Therefore, Janayda is correct.

While Sirr is incorrect.

Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.

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In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

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Step-by-step explanation:

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The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

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The margin of error is:

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In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

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