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2 years ago

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What is the value of the element at b23 ?

1 answer:

Leya [2.2K]2 years ago

4 0

$\qquad\qquad \textit{columns}\\ b=\begin{bmatrix} 6&-5&16\\ 3&22&\boxed{24}\\ 7&22&14 \end{bmatrix} \begin{array}{llll} r\\o\\w\\s \end{array}\qquad \impliedby \qquad \begin{array}{llll} b23\\ \textit{matrix "b"}\\ \textit{row 2}\\ \textit{column 3} \end{array}$

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Please help! algebra 1 math! whoever gets right is Brainliest! (10 points)

Inga [223]

I believe that 7 5/4 is the answer.

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2 years ago

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The ratio of Mary’s downloaded iPad apps to Katie’s is 12 to 8. If Katie has 96 apps how many does Mary have?

sladkih [1.3K]

8×12=96. Katie
12×12=144. Mary
you have to Divide Katie's 96 by 8 to get 12
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2 years ago

The center of a circle is at (−3, 1) and its radius is 9.

pickupchik [31]

Answer:

Sorry but the correct answer is (x+3)2+(y−1)2=81

Step-by-step explanation:

Because the radius squared is the answer of the equation

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3 years ago

Find the area of this shape. Correct answer will Brainliest

Iteru [2.4K]

Answer:

As shown in picture, this is a trapezoid.

The area of a trapezoid is calculated by:

A = (base1 + base2) x height x (1/2)

To work out A, we need to find out base1, base2, and height.

base1 = YZ = $\sqrt{(Zx - Yx)^{2} + (Zy - Yy)^{2} } = \sqrt{(5 - 2)^{2} + (5 - 5)^{2} } = 3$

base2 = XW = $\sqrt{(Wx - Xx)^{2} + (Wy - Xy)^{2} } = \sqrt{(8 - 1)^{2} + (1 - 1)^{2} } = 7$

Otherwise, the height (distance between base1 and base2) is 4 as shown in picture.

=> A = (3 + 7) x 4 x (1/2) = 20

Hope this helps!

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6 0

2 years ago

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12

Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

$P(x)=-12x^2+120x$

To find:

The current that will produce the maximum power.

Solution:

We have,

$P(x)=-12x^2+120x$

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, a=-12 and b=120. So,

$-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}$

$-\dfrac{b}{2a}=-\dfrac{120}{-24}$

$-\dfrac{b}{2a}=5$

Putting x=5 in the given function, we get

$P(5)=-12(5)^2+120(5)$

$P(5)=-12(25)+600$

$P(5)=-300+600$

$P(5)=300$

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0

2 years ago