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polet [3.4K]
3 years ago
10

Tom, Brad, Angela, and Mona went to a theater. In how many different ways can they sit on four adjacent seats in a line in the t

heater?
Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

Answer:

16

Step-by-step explanation:

4x4 = 16

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Savannah uses models to compare two decimal numbers. She says 0.35 is greater than 0.4 because 35 > 4.Which of these explains
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

La primera ya que es .35 y .40 hay que igualar

4 0
3 years ago
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Stephanie puts 30 cubes in a box. the cubes are 1/ inch on each side. the box holds two layers with 15 cubes in each layer. what
-BARSIC- [3]

v = lwh \\ v = 15 \times 15 \times 2 \\ v = 450 \: cubic \: in
The shape is a rectangle, btw
4 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary). 50, 60,72,... Find the 8th term.
Vadim26 [7]

Answer:

179.159

Step-by-step explanation:

Given the sequence :

50, 60, 72,..

The sequence given is a geometric sequence :

For a geometric sequence ;

ar^(n - 1)

a = first term

r = a2 / a1 = 60 / 50 = 1.2

The 8th term ; n =8

a8 = ar^(n - 1)

a8 = 50*1.2^(8 - 1)

a8 = 50*1.2^7

a8 = 50*3.5831808

a8 = 179.15904

a8 = 179.159 (nearest thousandth )

8 0
3 years ago
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
4 years ago
Which relation Is a function? From the graphs ​
kicyunya [14]

Answer:

3rd one

Step-by-step explanation:

because it's close

5 0
4 years ago
Read 2 more answers
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