<span> By definition, the volume of a cone is given by:
</span>

<span> Where,
r: radius of the circular base of the cone.
h: cone height
The cone radius is given by:
</span>

<span> Where,
d: diameter of the circular base.
Substituting values we have:
</span>

<span>
Then, the volume will be:
</span>

<span>
Answer:
The volume of the cone is given by:
</span>

<span>
</span>
Answer:
ΔABC≅ΔDEC by AAS
Step-by-step explanation:
You can use the AAS method of congruency.
Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent
Hope this helped.