Answer:
50.24 yd^2
Step-by-step explanation:
The area of a circle can be found using:
First, we need to find the radius. We have the diameter. The diameter is twice the radius, or
d=2r
We know that the diameter is 8, so we can substitute 8 in for d
8=2r
Since we are trying to find r, we need to get r by itself. To do this, divide both sides by 2.
8/2=2r/2
4=r
Now we know the radius, and can substitute 4 in for r. Also, we can substitute 3.14 in for pi.
a=3.14*4^2
Solve the exponent
a=3.14*16
Multiply
a=50.24
The area is 50.24 yards^2
Monthly depreciation is calculated as follows:
65,000 (Cost) – 5,000 (Salvage Value) ÷ 60 (5 years X 12 months per year) = 1,000 in depreciation per month.
a) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 36,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 2,000
b) Accumulated depreciation from 1/1/12 to 5/1/15 is 40,000 (12 months for 2012, 2013, 2014, & 4 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
5/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 40,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 6,000
c) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 36,000
Loss on Sale of Equipment (DR) 18,000
Equipment (CR) 65,000
d) Accumulated depreciation from 1/1/12 to 10/1/15 is 45,000 (12 months for 2012, 2013, 2014, & 9 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
10/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 45,000
Loss on Sale of Equipment (DR) 9,000
Equipment (CR) 65,000
Not my answers, but I hope this will help you. :)
we know that
total of sum of arc is 360
so, sum of both arc must be 360
so, we get
now, we can solve for x
............Answer
