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Vika [28.1K]
2 years ago
12

there is 1/4 of a pan of brownies on the kitchen counter. you and your friend want to split it evenly do you each take 1/2 of wh

ats left. what fraction of the whole pan do you each get? draw a picture to show
Mathematics
1 answer:
Ber [7]2 years ago
4 0

Answer:

1/4 of the pan of brownies

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Determine the measure of an angle that is three-fourths of a full turn.
Agata [3.3K]

Answer:

270

Step-by-step explanation:

6 0
3 years ago
Can anyone help me??? <br><br> PLZ….
bezimeni [28]
7. Obtuse
8. Acute
9. No, because it’s the hypotenuse
10. Yes, because that part is not the hypotenuse and it is less than the greatest angle
4 0
3 years ago
Find the value of x :)
Damm [24]

Answer:

x=65

Step-by-step explanation:

130+75+90+x=360

add 130 75 and 90 together to simplify

295+x=360

subtract 295 by both sides to isolate x

x=65

hope that helped!

8 0
3 years ago
I need help plzz its due TODAYYY
kobusy [5.1K]

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

4th box: Zero prop: m x 0=0

3 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
4 years ago
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