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devlian [24]
3 years ago
9

What is 2/3, 7/6, 3 1/9, and 5 5/18 written as a decimal?

Mathematics
2 answers:
AveGali [126]3 years ago
8 0
Ok done. Thank to me :>

Paul [167]3 years ago
4 0

Step-by-step explanation:

\frac{2}{3}  = 2  \times  \frac{1}{3}  = 2 \times 0.333 = 0.666 \\  \\  \frac{7}{6}  = 7 \times  \frac{1}{6}  = 7 \times  \frac{1}{2}  \times  \frac{1}{3}  = 7 \times 0.5 \times 0.333 = 1.1655 \\  \\ 3 \frac{1}{9}  = 3 +  \frac{1}{9}  = 3  + ( \frac{1}{3}  \times   \frac{1}{ 3} ) = 3 + (0.333 \times 0.333) = 3 \times 0.11088 = 3.11088 \\  \\ 5 \frac{5}{18}  = 5 + (5 \times  \frac{1}{18} ) = 5 + (5 \times   \frac{1}{3}  \times  \frac{1}{3}  \times  \frac{1}{2} ) = 5 +(5 \times 0.333 \times 0.333 \times 0.5) = 5 + 0.27722 = 5.27722

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<img src="https://tex.z-dn.net/?f=38688%20%5Cdiv%20624%20%3D%20" id="TexFormula1" title="38688 \div 624 = " alt="38688 \div 624
marusya05 [52]
Divide 38688 by 624 to get 62.
62.

3 0
3 years ago
a football match,the ratio of children to adults is 2:7.there are 2700 people int he crowd. each adult ticket is £8 each child t
marusya05 [52]

Step-by-step explanation:

since the ratio of children to adult is 2:7,

2+7 = 9

number of children would be

(2 × 2700)/9 = 600 children in the crowd

number of adults would be

(7 × 2700)/9 = 2100 adults in the crowd

So, if a ticket costs £8 per adults, total cash made from adult

= 8 × 2100 = £16800

if a ticket costs £(8 - 3) per children, total cash made from children

= 5 × 600 = £3000

total money made = £(16800 + 3000)

= £19800

7 0
3 years ago
Write 2 In 6 + 3 In 4 - 5 In (1/3) as a single logarithm
liberstina [14]

Answer:

ln 559872

Step-by-step explanation:

2 In 6 + 3 In 4 - 5 In (1/3) = ln 6² + ln 4³ - ln (⅓)⁵

= ln 36 + ln 64 - ln 1/243

= ln [(36×64)/(1/243)]

= ln 559872

3 0
3 years ago
In the manufacturing of a chemical adhesive, 9% of all batches have raw materials from two different lots. This occurs when hold
natali 33 [55]

Answer:

Step-by-step explanation:

Hello!

In a chemical adhesive manufacturing company you can encounter the following situations:

The adhesive is made in batches.

9% of all batches have raw materials from two different lots.

5% of all batches with material from a single lot require reprocessing.

40% of all batches with the material of two or more lots require additional processing.

You have two events:

A: A batch is formed with two different lots.

B: The lot requires additional processing.

And you can define their complements:

A': A batch is formed with one lot.

B': The lot does not require additional processing.

a. This probability is given in the text "9% of all batches have raw materials from two different lots. ", symbolically:

P(A)= 0.09

b. If the probability of a batch containing two lots is 9%, then it's complimentary event has a probability equal to:

P(A')= 1 - 0.09= 0.91

c. P(B/A) It is a conditional probability and you can interpret it as "the lot requires additional processing given that the batch is formed with two lots"

This information is also given:

P(B/A)= 0.40

d. P(B/A') Is the probability of the lot requiring additional processing given that the batch is formed with one lot.

P(B/A')= 0.05

e. Now you have to calculate the probability that "the batch is made with two lots" and "the lot requires additional processing"

A and B aren't independent events, which means that the occurrence of one of them modifies the probability of occurrence of the other one in two replications of the experiment.

P(A ∩ B)= P(A) * P(B/A)

P(A ∩ B)= 0.09 * 0.40= 0.036

f. You have to calculate the probability of "batch is formed with two different lots" and "the lot does not require additional processing", these two events aren't independent.

You cannot calculate the probability of this intersection the same way you did in item e. because we have no information about the probability of P(B'/A). But the P(A) is equal to the summation of P(A ∩ B) and P(A ∩ B'), so:

P(A ∩ B')= P(A) - P(A ∩ B)= 0.09 - 0.036= 0.054

g. To calculate the probability of the event "The lot requires additional processing." you have to add P(A ∩ B)+P(A' ∩ B)

First calculate P(A' ∩ B) = P(A')* P(B/A')= 0.91*0.05= 0.0455

P(B)= P(A ∩ B) + P(A' ∩ B)= 0.036 + 0.0455= 0.0815

I hope you have a SUPER day!

8 0
3 years ago
A line passes through (0,4) and (3,0). Which equation does not represent the equation of this line?
Olenka [21]

Answer:

A

Step-by-step explanation:

use both points to find the slope using the equation

y2-y1/x2-x1, so , -2-4/2-0 = -6/2 = -3. slope or m = -3

then the y int can be any y point, so either -2 or 4. in this case they used 4.

7 0
3 years ago
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