Answer:
yes
Step-by-step explanation:
31/7 = 4 3/7.....3/7 is less then 1/2....so the closest integer is 4
The answer in 27 $$$$$$$$$$$$$$$$$$$$$$$$
x is the temperature and y is the number of swimmers. If there are 80 swimmers, then y = 80 instead of x = 80
This is how Corey should have solved
y = 1.505*x - 88.21
80 = 1.505*x - 88.21 <--- replace y with 80
1.505*x - 88.21 = 80
1.505*x = 80 + 88.21 <--- add 88.21 to both sides
1.505*x = 168.21
x = 168.21/1.505 <--- divide both sides by 1.505
x = 111.767
x = 111.8
If there are 80 swimmers at the pool, then the possible outside temperature is roughly 111.8 degrees F. This temperature seems awfully large, so it's possible that Corey's regression equation has limited scope; in other words, it isn't too useful if x is outside a given interval
<h2>
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Answer: 0.7748
Step-by-step explanation:
Given : Number of bit bulls at the pound = 18
Number of pit bulls have attacked another dog in the last year =4
The proportion of pit bulls have attacked another dog in the last year:![p=\dfrac{4}{18}\approx0.22](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7B4%7D%7B18%7D%5Capprox0.22)
Number of the pit bulls selected = 6
The probability of that none of the pit bulls in Joe's group attacked another dog last year : ![P(0)=(1-0.22)^6=0.225199600704\approx0.2252](https://tex.z-dn.net/?f=P%280%29%3D%281-0.22%29%5E6%3D0.225199600704%5Capprox0.2252)
By using binomial , the probability that at least one of the pit bulls in Joe's group attacked another dog last year is given by :-
![P(x\geq 1)=1-P(x](https://tex.z-dn.net/?f=P%28x%5Cgeq%201%29%3D1-P%28x%3C1%29%5C%5C%5C%5C%3D1-P%280%29%5C%5C%5C%5C%3D1-0.2252%3D0.7748)
Hence, the required probability = 0.7748