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Musya8 [376]
2 years ago
8

A store sells 4 varieties of donuts. Chocolate and Jelly are two of the varieties sold. How many ways are there to select 14 don

uts so that at least 5 Chocolate donuts and at most 4 Jelly donuts are selected
Mathematics
1 answer:
Margaret [11]2 years ago
7 0

Answer:

1 way.

Step-by-step explanation:

1) 10 Chocolate Donuts and 4 Jelly Donuts

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A bag contains 8 purple marbles & 12 green marbles. You choose one marble out of the bag without looking.
MrRissso [65]

Answer:

1. P(P) = 8/20 = 0.4

2. P(G) = 12/20 = 0.6

Step-by-step explanation:

Given;

Number of green marbles G = 12

Number of purple marbles P = 8

Total T = 12+8 = 20

The probability that you choose a purple marble P(P) is;

P(P) = number of purple marbles/total number of marbles

P(P) = P/T = 8/20 = 0.4

P(P) = 0.4

The probability that you choose a Green marble P(G) is;

P(G) = number of Green marbles/total number of marbles

P(G) = G/T = 12/20 = 0.6

P(G) = 0.6

6 0
3 years ago
In the graphic below, ARV = ENV by:
GREYUIT [131]
The ans should be ASA because angle AVR is equal to angle EVN (opposite angles equal) 
8 0
3 years ago
A student estimated a mass to be 250 grams but upon carefully measuring it, he found the actual mass to be 240 grams. What is th
disa [49]
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6 0
2 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
A-(buc)=(A-b)u(A-c)<br>​
kupik [55]

Step-by-step explanation:

I don't get the question a bit but I hope this makes sense

:)

5 0
3 years ago
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