48 = 2(w+4) + 2w
48 = 4w+8
40 = 4w
w= 10 yd
A= 10 * 14
A = 140 yd
Answer:
y = 12
Step-by-step explanation:
∵ m∠ABC = 40
∵ BD ray is the bisector of ∠ABC
∴ m∠ABD = m∠CBD = 20
In 2 Δ BAD and BCD:
∵ m∠BAD = m∠BCD = 90°
∵ m∠ABD = m∠CBD = 20°
∵ BD is a common side in the two triangles
∴ ΔABD congruent to ΔCBD⇒(AAS)
∴ AD = CD
∴ 3y + 6 = 5y - 18
∴ 5y - 3y = 6 + 18
∴ 2y = 24
∴ y = 24/2 = 12
I'll try it.
I just went through this twice on scratch paper. The first time was to
see if I could do it, and the second time was because the first result
I got was ridiculous. But I think I got it.
You said <span><u>3sin²(x) = cos²(x)</u>
Use this trig identity: sin²(x) = 1 - cos²(x)
Plug it into the original equation for (x).
3(1 - cos²(x) ) = cos²(x)
Remove parentheses on the left: 3 - 3cos²(x) = cos²(x)
Add 3cos²(x) to each side: 3 = 4cos²(x)
Divide each side by 4 : 3/4 = cos²(x)
Take the square root of each side: <em>cos(x) = (√3) / 2</em> .
There it is ... the cosine of the unknown angle.
Now you just go look it up in a book with a table cosines,
or else pinch it through your computer or your calculator,
or else just remember that you've learned that
cos( <em><u>30°</u></em> ) = </span><span><span>(√3) / 2 </span>.
</span>
When they can no longer afford the mortgage but before they miss a payment.
