A formula<span> for the number of possible </span>combinations<span> of </span>r<span> objects from a </span>set<span> of </span>n<span> objects. For this, order is not important. We calculate it as follows:
nCr
9C7
36 <-------last option</span>
Answer:
100.9 yards
Step-by-step explanation:
One circuit of the track is a distance of ...
C = 2πr = 2π(60 yd) = 120π yd.
At Alex's running rate, the distance covered in 20 minutes is ...
(4 yd/s)(20 min)(60 s/min) = 4800 yd
The number of circuits will be ...
(4800 yd)/(120π yd/circuit) = 40/π circuits ≈ 12.7324 circuits
The last of Alex's laps is more than half-completed, so the shortest distance to his starting point is 13 -12.7324 = 0.2676 circuits,
That distance is (0.2676 circuits)×(120π yd/circuit) ≈ 100.88 yd
The shortest distance along the track to Alex's starting point is about 100.9 yards.
_____
<em>Additional comment</em>
The exact distance is 120(13π-40) yards. The distance will vary according to your approximation for pi. If you use 3.14, this is about 98.4 yards.
V = LXHXW
V = 12X20X8 = 1920
Answer:
144 carrots
Step-by-step explanation:
Let C stand for the number of carrots that a student can plant.
We are told that carrots may be planted at a density of 9 carrots/ft^2.
Let A be the area, in ft^2, that can be planted with carrots. The area of a rectangle is Base x Length (in feet).
We can therefore write:
C = (9 carrots/ft^2)*A
In the garden shown, the area is A = (4 ft) x (4 ft) = 16 ft^2
C = 9 carrots/ft^2)*(16 ft^2)
C = 144 carrots
Answer:
x = 6.3375
Step-by-step explanation:
sin53 = 4/5 (roughly) = 5.07/x
=> 4x = 25.35
=> x = 6.3375