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Advocard [28]
3 years ago
7

Steps of 17/3 - 3/4x = 1/2x + 5

Mathematics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

Step-by-step explanation:

12(17/3 - 3/4x = 1/2x + 5)

68 - 9x = 6x + 60

-15x = -8

x = 8/15

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2- x= -2 y= -1 so the slope is -1/-2
3- x= 2 y= 3 so the slope is 1 1/2
i’m not sure if this is right but i’m learning this as well
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3 years ago
If f(x) and g(x)=x, determine the value(s) of x that satisfy the f(x)=g(x).
lions [1.4K]

Answer: All values make a true statement.

Step-by-step explanation: Since f(x) and g(x)=x, f(x)=g(x) can also be written as x=x. That is a true statement so all values of x works.

Hope this helps!

3 0
3 years ago
What the slope of(7,3) (6,-2)​
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slope =  \frac{ - 2 - 3}{6 - 7}  \\

slope =  \frac{ - 5}{ - 1}  \\

slope = 5

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6 0
3 years ago
Neeeeeed heeelp plz!!!
Blababa [14]
                             |
                             |__x_- 4___________              2x³/2x² =x
   2x² + 2x +3        | 2x³ - 6x² +7x +3
                            - (<span>2x³ +2x² +3x)
</span>                                      -8x² +4x  +3                -8x²/2x² = -4
                                    <span>-(-8x² -8x  -12)
</span>                                              12x +15

(x-4) + (12x +15)/(2x² + 2x +3) 
6 0
4 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
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