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yanalaym [24]
3 years ago
6

Is this a function or a non function?​

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

This is a function

Step-by-step explanation:

If you do the Vertical Line Test you can see that the line passes through only one dot at a time. Therefore it is a function. If the line passed through more than one dot at a time then it wouldn't be a function.

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Write the first four terms of the sequence defined by each of the following recursive formulas.
diamong [38]
A1 = 3 and an = an − 1 − 3
a1 = 2 and an = an − 1 + 0.5
6 0
3 years ago
What are the solution(s) to the quadratic equation 9x2 = 4?
Oksanka [162]

we have

9x^{2}=4

Divide both sides by 9

9x^{2}/9=4/9

x^{2}=4/9

Square root both sides

x=(+/-)\sqrt{\frac{4}{9}}

x=(+/-)\frac{2}{3}

so

the solutions are

x1=\frac{2}{3}

x2=-\frac{2}{3}

therefore

<u>the answer is the option</u>

x = 2/3 and x = -2/3

8 0
3 years ago
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Write the trigonometric expression in terms of sine and cosine, and then simplify. cot()/sin()-csc()
OLEGan [10]

Answer:

First, we know that:

cot(x) = cos(x)/sin(x)

csc(x) = 1/sin(x)

I can't know for sure what is the exact equation, so I will assume two cases.

The first case is if the equation is:

\frac{cot(x)}{sin(x)} - csc(x)

if we replace cot(x) and csc(x) we get:

\frac{cot(x)}{sin(x)} - csc(x) = \frac{cos(x)}{sin(x)} \frac{1}{sin(x)}  - \frac{1}{sin(x)}

Now let's we can rewrite this as:

\frac{cos(x)}{sin(x)} \frac{1}{sin(x)}  - \frac{1}{sin(x)} =\frac{cos(x)}{sin^2(x)} - \frac{1}{sin(x)}

\frac{cos(x)}{sin^2(x)}  - \frac{sin(x)}{sin^2(x)} = \frac{cos(x) - sin(x)}{sin^2(x)}

We can't simplify it more.

Second case:

If the initial equation was

\frac{cot(x)}{sin(x) - csc(x)}

Then if we replace cot(x) and csc(x)

\frac{cos(x)}{sin(x)}*\frac{1}{sin(x) - 1/sin(x)} = \frac{cos(x)}{sin(x)}*\frac{1}{sin^2(x)/sin(x) - 1/sin(x)}

This is equal to:

\frac{cos(x)}{sin(x)}*\frac{sin(x)}{sin^2(x) - 1}

And we know that:

sin^2(x) + cos^2(x) = 1

Then:

sin^2(x) - 1 = -cos^2(x)

So we can replace that in our equation:

\frac{cos(x)}{sin(x)}*\frac{sin(x)}{sin^2(x) - 1} = \frac{cos(x)}{sin(x)}*\frac{sin(x)}{-cos^2(x)} = -\frac{cos(x)}{cos^2(x)}*\frac{sin(x)}{sin(x)}  = - \frac{1}{cos(x)}

5 0
3 years ago
How do i find the missing length indicated
SCORPION-xisa [38]

Answer:

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Step-by-step explanation:

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3 years ago
.000001 equals 1 x 10-4 Answer <br> a. True<br> b. False
RSB [31]
Im pretty sure the answer is false
5 0
4 years ago
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