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3 years ago

Help me please everyone;-;

Mathematics

2 answers:

Lana71 [14]3 years ago

6 0

Step-by-step explanation:

$( \frac{ {x}^{4} }{ {x}^{3} } ) ^{ - 4 } \\ ( {x}^{4 - 3} ) ^{ - 4} \\ (x ^{1} ) ^{ - 4} \\ x ^{1 \times - 4} \\ x ^{ - 4}$

Debora [2.8K]3 years ago

4 0

Answer:

x - 4

Step-by-step explanation:

$\sf \bigg( \dfrac{ {x}^{4} }{ {x}^{3} } \bigg) - 4$

$\sf \bull \dfrac{{a}^{m} }{ {a}^{n} } = {a}^{m - n}$

$\sf \: {x}^{4 - 3} - 4$

$\sf{x}^{1} - 4$

$\sf \: x - 4$

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The volunteers at a high school football team's concession stand are trying to decide on the price of the hot dogs they are sell

Dovator [93]

Answer:

The constant term in the polynomial is 140 and it represents the revenue when the price is not increased.

Step-by-step explanation:

To find: What is the constant term in the polynomial expression, and what does it represent?

The given expression is $-8x^2 + 54x + 140$ .

To find the constant term we can simply put x=0 in the given equation where x represents the number of $1 increase in price.

= $-8(0)^2 + 54(0) + 140$

= $140$

The constant term is 140 and it represents the revenue when the cost of a hot dog is $2.

Hence, the constant term in the polynomial is 140 and it represents the revenue when the price is not increased.

8 0

3 years ago

The circle below is centered at the origin and has a radius of 4. What is its equation?

Alecsey [184]

Answer:

C) x^2 + y^2 = 16

Step-by-step explanation:

<h2><u>Find the equation </u></h2>

since the radius is 4 this means that anywhere from the center of the circle to the edge of the circle is 4. hence :

place the horizontal line of the radius where y = 0 .

this means that if y = 0 , then x = 4

therefore :

x^2 + y^2

4^2 + 0^2

= 16

<h3><u>hence the answer is C ) x^2 + y^2 = 16</u></h3>

7 0

3 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

3 years ago

Which of the following are solutions to the equation below? Check all that apply. x2 + x - 20 = 0

Mila [183]

Δ = 1 + 4*20 = 81
x' = (-1 + 9)/2 = 4
x'' = (-1 - 9)/2 = -5
4² + 4 - 20 = 0
(-5)² - 5 - 20 = 0
Ok !

7 0

3 years ago

Read 2 more answers

Use two points to enter an equation for the function. Give your answer in the form a (b^x). In the event

melomori [17]

Answer:

LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right, good luck, i tried to give you the right answer so if its wrong then its the system!

Step-by-step explanation:

8 0

3 years ago